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Rank apps matching a whole word of the query above exact menu entries

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Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
This commit is contained in:
David Heinemeier Hansson
2026-07-31 20:22:05 -04:00
co-authored by Claude Fable 5
parent a79d1dc8da
commit 15cecc9748
2 changed files with 11 additions and 1 deletions
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test/shell.d/menu-test.sh
+8 -1
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@@ -115,7 +115,8 @@ const defaultById = Object.fromEntries(defaultItems.map(item => [item.id, item])
const rankBase = menu.mergeMenuSources(defaultItems, [])
const ranked = menu.mergeAppRows(rankBase.items, rankBase.itemOrder, [
{ id: 'apps.brave', parent: 'apps', kind: 'app', label: 'Brave', description: '', aliases: [] },
{ id: 'apps.fontforge', parent: 'apps', kind: 'app', label: 'FontForge', description: '', aliases: [] }
{ id: 'apps.fontforge', parent: 'apps', kind: 'app', label: 'FontForge', description: '', aliases: [] },
{ id: 'apps.zen', parent: 'apps', kind: 'app', label: 'Zen Browser', description: '', aliases: [] }
])
const rankScore = (id, query) => menu.searchScore(ranked.items, ranked.items[id], query)
assert(
@@ -124,6 +125,12 @@ assert(
),
'menu ranks an installed app above menu entries matching the query equally well'
)
assert(
['install.browser.zen', 'remove.browser.zen', 'setup.default.browser.zen'].every(
id => rankScore('apps.zen', 'zen') < rankScore(id, 'zen')
),
'menu ranks an app matching the query as a whole word above exact-labeled menu entries'
)
assert(
rankScore('style.font', 'font') < rankScore('apps.fontforge', 'font'),
'menu keeps a better-matching menu entry above a weaker app match'