Files
2b9e2720b3 Run every test file instead of stopping at the first failure (#6622)
test/shell and test/all inherit `set -euo pipefail`, so the first failing
test file aborts the whole run. One failure then hides every file behind it:
you fix it, rerun, discover the next one, and repeat a file at a time. On a
140-file suite a single unrelated failure can keep most of the suite from ever
reporting.

Keep going after a failing file, then list the files that failed and exit
non-zero. Individual files still stop at their own first failed assertion, so
per-file isolation is unchanged, and a clean run still exits 0.

The files are already independent of each other -- the set of failures is the
same whether the run continues or stops at the first one -- so nothing was
relying on the early abort.

Co-authored-by: Claude Opus 5 (1M context) <noreply@anthropic.com>
2026-08-08 08:57:36 +02:00

37 lines
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Bash
Executable File

#!/bin/bash
set -euo pipefail
ROOT=$(cd -- "$(dirname -- "${BASH_SOURCE[0]}")/.." && pwd)
TEST_DIR="$ROOT/test/shell.d"
shopt -s nullglob
tests=()
for test in "$TEST_DIR"/*-test.sh; do
[[ $(basename "$test") == "base-test.sh" ]] && continue
tests+=("$test")
done
shopt -u nullglob
if (( ${#tests[@]} == 0 )); then
echo "No shell tests found in $TEST_DIR" >&2
exit 1
fi
# Keep going after a failing file. A test file exits at its first failed
# assertion, so aborting the run there too would hide every file after it --
# one packaging failure was masking 114 of 134 files.
failed=()
for test in "${tests[@]}"; do
printf '==> %s\n' "${test#$ROOT/}"
bash "$test" || failed+=("${test#$ROOT/}")
done
if (( ${#failed[@]} > 0 )); then
printf '\n%d of %d test files failed:\n' "${#failed[@]}" "${#tests[@]}" >&2
printf ' %s\n' "${failed[@]}" >&2
exit 1
fi
printf '\nAll %d test files passed.\n' "${#tests[@]}"